I need a probability expert

Mythmere · Post by **Mythmere** » Tue Nov 28, 2006 6:40 pm

If there's an opposed roll, a d6 versus a d8...
You are subtracting the d6 from the d8, and if the difference is 4 or more (in favor of the d8), then there's success.

How would I calculate the percentage chance that my d8 roller is going to succeed? Can anyone whip up a formula for this calculation?

GenghisWayne · Post by **GenghisWayne** » Tue Nov 28, 2006 8:10 pm

Not sure I can help with a formula; grad school is too far in the past; but the answer is 10/48 or about 21% chance. I just think of a matrix, one axis is the d8 result the other axis is the d6 result, cells show the difference in rolls. Count up the ones with a difference of 4 or more; there are 10 of those and 48 cells in all.

HTH,
GW-

Stik · Post by **Stik** » Tue Nov 28, 2006 9:51 pm

That'll work quite nicely. An elegant solution GW.

Mythmere · Post by **Mythmere** » Wed Nov 29, 2006 8:04 am

Thanks a million, GW!

Algolei · Post by **Algolei** » Wed Nov 29, 2006 10:41 pm

GenghisWayne wrote:Not sure I can help with a formula; grad school is too far in the past; but the answer is 10/48 or about 21% chance. I just think of a matrix, one axis is the d8 result the other axis is the d6 result, cells show the difference in rolls. Count up the ones with a difference of 4 or more; there are 10 of those and 48 cells in all.

HTH,
GW-

That's the way to do it, GW. Any formula would be a derivation of that method.

Logic for the win!