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I need a probability expert
Posted: Tue Nov 28, 2006 6:40 pm
by Mythmere
If there's an opposed roll, a d6 versus a d8...
You are subtracting the d6 from the d8, and if the difference is 4 or more (in favor of the d8), then there's success.
How would I calculate the percentage chance that my d8 roller is going to succeed? Can anyone whip up a formula for this calculation?
Posted: Tue Nov 28, 2006 8:10 pm
by GenghisWayne
Not sure I can help with a formula; grad school is too far in the past; but the answer is 10/48 or about 21% chance. I just think of a matrix, one axis is the d8 result the other axis is the d6 result, cells show the difference in rolls. Count up the ones with a difference of 4 or more; there are 10 of those and 48 cells in all.
HTH,
GW-
Posted: Tue Nov 28, 2006 9:51 pm
by Stik
That'll work quite nicely. An elegant solution GW.
Posted: Wed Nov 29, 2006 8:04 am
by Mythmere
Thanks a million, GW!
Posted: Wed Nov 29, 2006 10:41 pm
by Algolei
GenghisWayne wrote:Not sure I can help with a formula; grad school is too far in the past; but the answer is 10/48 or about 21% chance. I just think of a matrix, one axis is the d8 result the other axis is the d6 result, cells show the difference in rolls. Count up the ones with a difference of 4 or more; there are 10 of those and 48 cells in all.
HTH,
GW-
That's the way to do it, GW. Any formula would be a derivation of that method.
Logic for the win!
